If that's true for an on/off wall switch.īut that's different. If your talking about the new led bulbs with incandescent lamp compatible screw in baseĬonnectors I know they are dimly lit when you That's a little bit more than 120 or 230V. Typical contacts are at least 1 to 10mm apart (depending on the type). Stray capacitance doesn't conduct across open contacts. You're obviously talking about something other than open or closed contacts. I've been working with AC relays and contactorsįor forty years and never seen an AC load with power when the contacts are open. Wires on the cord and then plug it in and turn on the light, take a photo of the 'dim' light and post it Test: Take an AC lamp cord, cut one of the two I'm havin trouble understanding how it can 'alternate' if the circuit loop is OPEN'. I always thought 'AC' meant Alternating Current. It is not shining brightly (like when relay is in LOW state), but only dim." "Although relay is in HIGH state (which the led strip should be completely off), the led strip still on. What do you want to bet that the relay contacts are not where we think they are ? (not sure how that explains the magic 'powerless leds' What the OP is calling an AC led string is an AC/DC converter powering a constant current PS powering a string of leds. Led string" since there is no such thing as an "AC LED" (you can put leds back to back to make a bipolar led but it's still two dc leds) Just for the record, there is no such thing as an "AC If I were there I could solve it 10 seconds. Way to do the impossible: make leds light with NO There is just no way the leds can be lit when power is removed so I must conclude the OP has found a or somehow it is not wired like we think it is. So clearly there is something wrong with this whole Where the OP connected the relay contacts that those leds are going to be as OFF as they could be We must conclude that something is wrong because I guarantee you that if I cut that led string in half Since energy can neither be created or destryed, Please let me know, how to make HIGH = 5V (enough voltage to drive 5V relay) without damaging D1 Mini signal pin? If it's much higher you risk damaging the Arduino.ĭMM measurement result on D1 Mini signal output: Arduino", but doesn't say 5V or 3.3V supply.Īs suggested, just check with a meter (or a battery and test lamp) whether the relay contacts are closing (and opening, for that matter!).Īlso, if you have a DMM, measure the voltage at the board input pin when the Arduino output is LOW. Blurb also says " It can be controlled directly by. Arduino, well, it's a bit doubtful with a 3.3V supply (I OL = 5mA). The signal input current is not specified, and the schematic is little help, as none of the component values nor device type numbers is given.īlurb claims it can be driven by TTL (I OL = 16mA). Unfortunately, the documentation from Sainsmart is one of the saddest apologies for a documentation set I've ever met.
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